Post #2339316

2026-05-09 22:36 UTC

@caroline@chaosfem.tw technically if you glue every object to another object that's only one object at the end. Though it may be a bit difficult to put away 🤔

Replies (3)

@pthariensflame@social.treehouse.systems 2026-05-09 22:37

@viq@social.hackerspace.pl @caroline@chaosfem.tw At that point, by virtue of it being all of the objects and therefore belonging all of the places, it is automatically already put away where it is.

Open ##2339317
@iris@neuromatch.social 2026-05-10 00:31

@viq@social.hackerspace.pl @caroline@chaosfem.tw depends entirely on whether you're looping over the mutable list of all objects in the room or presorting and looping over a list of pairs of objects.

Open ##2339322
@argv_minus_one@mastodon.sdf.org 2026-05-10 01:58

@viq@social.hackerspace.pl If you glue each object to another object, then you end up with *at most* half as many objects. Each object could be glued to exactly one other object, in which case you get n÷2 objects. Gluing each object to two other objects results in n÷3 objects. Gluing all objects together results in n÷n objects, i.e. one object. @caroline@chaosfem.tw

Open ##2339324