Post #2064285
2026-05-06 05:30 UTC
This is just a quick sketch -- I haven't implemented leap days or anything like that.
Also there'll almost definitely need to be named months scattered around, just counting up to 365 would be bland.
I think I'll want different week-lengths, too -- I forgot when arbitrarily picking 5 that it'd mean that every day of that subyear would fall on the same day of the week every time.
(Although tbh maybe it'd be nice, having a guarantee that one third of the New Years will be on a weekend?)
(EDIT: No, wait. Not one third. 5/(5+7+18)=5/30=one sixth of the New Years.)
Replies (2)
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@josh@hactivedirectory.com 2026-05-06 06:08
@gaditb@icosahedron.website @Binder@petrous.vislae.town One plus two plus one plus one…
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@gaditb@icosahedron.website 2026-05-06 05:44
I don't yet have a closed-form solution for what day and year it will be N days from the start of the calendar, but I'm almost SURE there is one. The harder one would be deriving which and where the concurrent years are, if you just have today's day+year. Ah! No, wait, leap days. That'll probably throw somewhat of a wrench into even the first computation. MaYBE there's still a closed-form solution?