Post #3131824
2026-05-06 05:44 UTC
I don't yet have a closed-form solution for what day and year it will be N days from the start of the calendar, but I'm almost SURE there is one.
The harder one would be deriving which and where the concurrent years are, if you just have today's day+year.
Ah! No, wait, leap days. That'll probably throw somewhat of a wrench into even the first computation. MaYBE there's still a closed-form solution?
Replies (1)
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@gaditb@icosahedron.website 2026-05-06 05:44
(Also I'm realizing that for leap days, I could just use exactly the same leap-day computation as the Gregorian calendar, just simply using the year-number in the exact same way. Granted, in this system there might sometimes be two leap-years happening simulteneously, but almost certainly only ever overlapping a little bit! and it'll still work out asymptotically!)