2023-12-12 01:24 UTC
Replies (6)
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@mbonsma@mastodon.social 2023-12-12 01:25
We derived a theory with a "spherical cow in a vacuum" approach: we approximated each puzzle piece area as a circle, then calculated the area of the circles packed together. Our prediction: the unassembled area is sqrt(3) times the assembled area. Then we took data.
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@MHowell@mas.to 2023-12-12 05:19
@mbonsma@mastodon.social How much room does it take outside your head?
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@greystate@mastodon.social 2023-12-12 08:55
@mbonsma@mastodon.social @leekelleher@mastodon.social Curious to know if you've made any similar conclusions in your vast puzzle-streak? 😁
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@BerndGoldschmidt@mastodon.social 2023-12-12 10:18
@mbonsma@mastodon.social is it dependent on the shape of the pieces?
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@Chancerubbage@mastodon.social 2023-12-12 11:48
@mbonsma@mastodon.social @gruber@mastodon.social So you would want a table around at least 3x the area. 1 (area) assembled puzzle)+ >1.7(area) assuming all pieces unassembled flat on table, a the assembled working area.
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@platkus@mastodon.social 2023-12-14 06:06
@mbonsma@mastodon.social This, as stated, is obviously incorrect. Otherwise the boxes that the puzzles come in would be larger in area than the assembled puzzle. However they are always smaller in area than the assembled puzzle.