Post #3289052
2026-06-07 17:26 UTC
Replies (2)
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@gsuberland@chaos.social 2026-06-07 17:28
@matildalove@wetdry.world @valpackett@social.treehouse.systems EDIT: this post was wrong, removing content to avoid misinformation, see the reply by @niconiconi@mk.absturztau.be below. I completely forgot how this works, siiiigh (TL;DR the 5.1k are necessary to get ANY power from compliant USB-C PD sources)
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@ignaloidas@not.acu.lt 2026-06-07 18:52
@gsuberland@chaos.social @matildalove@wetdry.world @valpackett@social.treehouse.systems correction - if the device does not have anything at all (as in, no resistors on CC lines), a compliant power source will not present any voltage. This is one of the core safeties of USB C - since you can connect two sources together, no USB-C source should apply any voltage unless it is sure that the other side is a sink and will accept it (this is also part of the reason why all USB-C to USB-A cables only have plugs but not ports - a source can tolerate 5V on the input from a USB-C unaware power source, but only if it knows not to apply the power itself). Also, this lives purely on the USB-C side of things, USB PD specs only get into the active communication stuff that happens after the passive, resistor based negotiation is established.