Post #2107464
2026-05-06 12:07 UTC
@NickT6630 I'll watch the video sometime later on, just one more question, how many bits you needed to get that result ? I mean are 8.8 ( 16 bits, which means you need an intermediate 32 bits for multiplication ) sufficient for that ? I never tried yet ..
Replies (1)
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@NickT6630@mastodon.scot 2026-05-06 12:11
@gilesgoat its using 8.8 bits with resulting calculations using up to 16 bits and because of the low resolution its enough. In the description below the video there is a link to his github page where you can see the code he wrote. I had to write some of my own routines for my method of display.