Post #2064286
2026-05-06 05:18 UTC
That's a bit more than a month of consecutive days.
Format is
"d {{day in the current year}} of yr {{current year}} (wd {{weekday (number) in the current week}} / {{number of days in a week for the current year}} )"
Replies (1)
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@gaditb@icosahedron.website 2026-05-06 05:30
This is just a quick sketch -- I haven't implemented leap days or anything like that. Also there'll almost definitely need to be named months scattered around, just counting up to 365 would be bland. I think I'll want different week-lengths, too -- I forgot when arbitrarily picking 5 that it'd mean that every day of that subyear would fall on the same day of the week every time. (Although tbh maybe it'd be nice, having a guarantee that one third of the New Years will be on a weekend?) (EDIT: No, wait. Not one third. 5/(5+7+18)=5/30=one sixth of the New Years.)