Post #4282574
2026-07-31 15:22 UTC
@jasongorman@mstdn.business @nobsagile@mastodon.social @scrumschau@mastodon.social
So let's suppose there are three choices at D3, one of which will break D5 (so, of course, we choose it!).
When we get to D5, we have a problem. So we have to rework D3 -- and possibly D6 and D7, which depend on it.
(D5 also has three choices, one of which would break D3. But we won't do that, because we know about D3's choice(s) at that point.)
Replies (1)
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@jasongorman@mstdn.business 2026-07-31 15:23
@JeffGrigg@mastodon.social @nobsagile@mastodon.social @scrumschau@mastodon.social You may be overthinking this 🙂