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@bemmesr@mathstodon.xyz

Post #4009860

2026-07-22 10:33 UTC

@FishFace@ioc.exchange that makes sense, thank you. It's a choice to limit the placeholders to constant values. I still don't quite understand why the technique doesn't work if we don't make this restriction though. After all, there ought to be a way to discover which polynomial A(x) would satisfy the equation between the original polynomial fraction and our decomposed sum of fractions, wherein A(x) is one of the numerators. I could appreciate that in fact the technique is easier if we do make this restriction but I still would like to know where it fails otherwise. Surely we could still achieve those nice constant numerators in the case of linear denominators if we approached it this way, since a constant is also a polynomial, just of order zero.

Replies (1)

  • @FishFace@ioc.exchange 2026-07-22 10:39

    @bemmesr@mathstodon.xyz Let's consider a concrete example that I pinched off a YouTube cover image. If I understand correctly, you're asking why, instead of Bx + C, we don't just put something like D(x) in the right-hand numerator and work from there? And maybe even put E(x) in the left hand one?

    Open ##4009859