Post #3386561

2026-06-16 02:05 UTC

There’s a lower chance of getting hit on turn 1, but it takes more turns to sink a five space ship and all of the others than just one five space ship. The goal is to last more turns with at least one boat, not avoid getting hit for the longest. I don’t see the advantage. Unless you add an extra rule requiring you to shoot the same space multiple times.

Replies (1)

@iusemybrain@sh.itjust.works 2026-06-17 01:28

what are you going on about, that probability depends on the number of turns you get? last I checked it, no it does not depend on that. the argument I’m trying to make is it’s statistically less likely to hit that 5 point battleship (probability is 5%) compared to the 17 points in ships spread abitrarily (probability is 17℅). IT DOES NOT DEPEND ON THE NUMBER OF TURNS IT TAKES TO SINK ALL 5 BATTLESHIP’S. The probability does depend after the first event has occurred (where you’ve hit one of those pieces). Whether you get a hit on your first turn or the first hit in 30 turns, it does not matter. probability does not depend on the number of turns it takes. technically speaking the probability calculated at the beginning is when the number of trials (theoretically) approach to infinity. The 1/6 probability to role a six sided die on a number (for example, lets say 6) is after doing trial and error of rolling a 6. Now whether you get the 6 on the first try or the 100th try these are approximations of the 1/6 th probability. As you do more and more trials it does eventually converge to the 1/6 th probability. So yes, technically speaking someone could hit the standalone stacked battleship in one try, probability and statistics doesn’t concern that. So if that concerns you, psychologically manipulate your openent by putting your battleship in the first row.

Open ##3386560