Post #2923564
2026-04-29 01:28 UTC
To get the turtle Markov partition I started off with, you can follow the same steps, but using the projection along \((1, \xi^2)\) instead of \((1,-1)\), and them moving the control point to the underside of the turtle's shell. By good fortune, the shifted regions don't overlap in this case either.
(5/n)
Replies (1)
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@pieter@mathstodon.xyz 2026-04-29 01:44
Lastly, we turn our attention to the Spectre tiling. Things are much the same as before, although since the deflation involves a reflection, we need to use a vector \(v\) such that \(𝑣𝑀=λ𝑣̅,\) instead of a left eigenvector. The two images show Markov partitions (I'm assuming) for hats-in-turtles and turtles-in-hats respectively. (6/6)