Post #2740980

Some #GameTheory curiosity about the red / blue pill dilemma. If N = # of participants, assuming no way to discuss their options, the Nash equilibria happen to be the same as the Pareto optima: - all vote red = 1 option - there's a majority of blue votes = `sum(C(k, N) for k in ceil(N/2) .. N)` which is `2**(N - 1)` options (exactly if N is odd, approximate if N is even). So the number of Nash equilibria tends to N/2. If you vote blue, you're playing with your life at heads or tails! #Maths