Post #2516089
2026-04-17 16:08 UTC
Replies (1)
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@nilesjohnson@mathstodon.xyz 2026-04-17 16:10
Continuing the previous post, here is the monoidal naturality diagram for two objects z and w: Checking the a-parity, one composite is even but the other is odd. So, the two composites around the diagram are not generally equal. In particular, they are not equal when z and w are the unit object, 0, and a is a free invertible generator. The paragraph after the diagram gives this explanation: conjugation by a and a' are both symmetric monoidal functors, and are both monoidal naturally isomorphic to the identity. So, they are monoidal naturally isomorphic to each other, but the (1 3) permutation above is *not* that isomorphism. Instead, that isomorphism factors through the identity functor, so it involves just de/cancellation morphisms with no permutations of the object a past its inverse a'. I think that makes sense in retrospect, but also could be a source of confusion. (It definitely was for me!! One day while we were working on this I sent Nick a sequence of increasingly frantic/confused emails, followed the next morning by a long explanation of how useful it is to get a good night sleep.) (10/11)