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@IcedRaktajino@startrek.website

Post #2385564

2026-05-08 12:17 UTC

How does that work? Does YT pay out to creators based on the subscriber count alone? I've only ever heard "like and subscribe to help fund this channel" mentioned when the videos are monetized (e.g ads or sponsors). Or does PBS monetize their videos and uBlock just shields me from that? Not that I don't want this to be true since it's an easy way to help fund them, but I am curious how (or if) this works.

Replies (4)

  • On monetized accounts (which PBS is) YT pays out creators based on advertising revenue. The way they calculate that is a complex, proprietary algorithm, but essentially it's based on view count and retention, and skip rate. So subscribing and liking doesn't actually directly help to fund the channel, *HOWEVER* more subs and likes usually translates to your videos getting pushed to more and more people (based on a totally different, complex proprietary algorithm), which usually leads to more views, and therefore more ad revenue. I'm pretty sure us ad-blocking users are still *technically* contributing to the ad revenue, but over time it *can* affect the results that advertisers are seeing, and therefore could effect the amount of money they are willing to spend on advertising in the niche or demographic that your favorite creators fall into. Does that all make sense?

    Open ##2385572

  • @Rod_Orm@piefed.world 2026-05-08 12:51

    More engagement: more changes algorithm push video to recommended fronthome YouTube website

    Open ##2385573

  • @CannedYeet@lemmy.world 2026-05-08 18:32

    There's also YouTube Premium which pays creators a cut that's more than they get with the ads. I bet they need to accept ads to get a cut of that.

    Open ##2385577

  • @Zephorah@discuss.online 2026-05-08 13:27

    Each channel needs 1000? subscribers to monetize at all. And then there’s the algorithm. Searches often include items with more not less subscribers, and monetization flows from there. Your subscribe feeds the channel into the algorithm.

    Open ##2385578