Post #1643738
2026-04-18 14:35 UTC
Possible proof strategy for "if monotone or antitone in each dimension, then boundary is tame": assume wlog that it's monotone in every dimension. Construct the homeomorphism by projecting the boundary onto the hyperplane orthogonal to (1, 1, ... 1)
Replies (1)
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@jcreed@mastodon.social 2026-04-18 16:16
ah, I think I have a counterexample for "if boundary is tame, then occupancy must be monotone or antitone in each variable" This shape is not monotone or antitone in x.