Post #1266205
2026-04-17 16:41 UTC
a = aa + aaa .* a3(A(aa).a2;
Replies (1)
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@Windex007@lemmy.world 2026-04-17 17:24
//assign a as a function of aa,aaa,A,a3, and a2 Nailed it
2026-04-17 16:41 UTC
//assign a as a function of aa,aaa,A,a3, and a2 Nailed it